Solve for x: x^2+1=x

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- Jan 27th 2009, 06:03 PMDCHomageSolving for x
Solve for x: x^2+1=x

- Jan 27th 2009, 06:06 PMJhevon
this is a quadratic equation, do you know how to deal with those?

first note that you have $\displaystyle x^2 - x + 1 = 0$

next you would try to factor, but it won't work here, so the next move is to complete the square, or use the quadratic formula. can you continue? - Jan 27th 2009, 06:11 PMDCHomage
Let's see. Do I move the -x+1 over?

- Jan 27th 2009, 06:31 PMmr fantastic
- Jan 27th 2009, 06:32 PMJhevon
- Jan 27th 2009, 06:57 PMDCHomage
can't remember. I have been working at my full time job that i forgot about it.

- Jan 27th 2009, 07:05 PMJhevon
the easier way would be the quadratic formula. it says the following

the solution(s) to an equation of the form $\displaystyle ax^2 + bx + c = 0$ are given by $\displaystyle x = \frac {-b \pm \sqrt{b^2 - 4ac}}{2a}$

what would that give as the answer to this problem? - Jan 27th 2009, 07:12 PMDCHomage
Not sure. I have this so far

$\displaystyle x = \frac {x \pm \sqrt{x^2 - 4x^2}}{2x^2}

$ - Jan 27th 2009, 07:24 PMmr fantastic
- Jan 27th 2009, 07:39 PMDCHomage
I got this so far.

$\displaystyle x = \frac {1 \pm \sqrt{-3}}{2} $

- Jan 27th 2009, 07:42 PMmr fantastic
- Jan 27th 2009, 07:48 PMDCHomage
So, I can't solve for x?

- Jan 27th 2009, 07:52 PMmr fantastic