Find the zero(s) of the function: f(x) = [1/(x+1)] + [1/(x-2)] My answer is -1 and 2.
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x=-1 and x=2 would be the location of the vertical asymptotes. The only zero of the function is found at ( .5,0 )
so the answer is .5?
Yes. The only zero can be found at $\displaystyle (\frac{1}{2},0)$
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