1. ## Finding Zero(s)

Find the zero(s) of the function:

f(x) = [1/(x+1)] + [1/(x-2)]

My answer is -1 and 2.

2. x=-1 and x=2 would be the location of the vertical asymptotes. The only zero of the function is found at ( .5,0 )

3. so the answer is .5?

4. Yes. The only zero can be found at $(\frac{1}{2},0)$