write an equation of the line containing the given point and parallel to the given line.
(8,-9)
9x-2y=5
can someone just help me get started on this???
please and thanksss.
the parallel line will go through point (8,-9)
y = kx + n
9x - 2y = 5
2y = 9x -5
y = (9/2)x - 5/2 <<< the first line
Parallel lines have the same koeficient k.
k in your case = 9/2
now you insert the coordinates of the point through which the parallel line will go through.
-9 = (9/2) * 8 + n
- 9 = 36 + n
n = -45
y = (9/2)x -45
Here is an easy way.
Any line parallel to $\displaystyle 9x-2y=5$ look $\displaystyle 9x-2y=K$.
To find $\displaystyle K$ use the point $\displaystyle x=8\;\&\;y=-9$: $\displaystyle 9({\color{red}8})-2({\color{red}-9})=({\color{red}90}) $
So your line is $\displaystyle 9x-2y=90$
Note there is a ‘sign’ error in the above reply.
This method minimizes those type of errors.