Thread: parallel lines

write an equation of the line containing the given point and parallel to the given line.

(8,-9)
9x-2y=5


can someone just help me get started on this???


please and thanksss.

the parallel line will go through point (8,-9)

y = kx + n

9x - 2y = 5
2y = 9x -5
y = (9/2)x - 5/2 <<< the first line

Parallel lines have the same koeficient k.
k in your case = 9/2

now you insert the coordinates of the point through which the parallel line will go through.

-9 = (9/2) * 8 + n
- 9 = 36 + n
n = -45

y = (9/2)x -45

Originally Posted by annabananzaa

write an equation of the line containing the given point and parallel to the given line. (8,-9); 9x-2y=5

Here is an easy way.
Any line parallel to look .
To find use the point :
So your line is

Note there is a ‘sign’ error in the above reply.
This method minimizes those type of errors.