1. ## parallel lines

write an equation of the line containing the given point and parallel to the given line.

(8,-9)
9x-2y=5

can someone just help me get started on this???

2. the parallel line will go through point (8,-9)

y = kx + n

9x - 2y = 5
2y = 9x -5
y = (9/2)x - 5/2 <<< the first line

Parallel lines have the same koeficient k.
k in your case = 9/2

now you insert the coordinates of the point through which the parallel line will go through.

-9 = (9/2) * 8 + n
- 9 = 36 + n
n = -45

y = (9/2)x -45

3. Originally Posted by annabananzaa
write an equation of the line containing the given point and parallel to the given line. (8,-9); 9x-2y=5
Here is an easy way.
Any line parallel to $9x-2y=5$ look $9x-2y=K$.
To find $K$ use the point $x=8\;\&\;y=-9$: $9({\color{red}8})-2({\color{red}-9})=({\color{red}90})$
So your line is $9x-2y=90$

Note there is a ‘sign’ error in the above reply.
This method minimizes those type of errors.