write an equation of the line containing the given point and parallel to the given line.

(8,-9)

9x-2y=5

can someone just help me get started on this???

please and thanksss.

Printable View

- Jan 26th 2009, 09:06 AMannabananzaaparallel lines
write an equation of the line containing the given point and parallel to the given line.

(8,-9)

9x-2y=5

can someone just help me get started on this???

please and thanksss. - Jan 26th 2009, 09:15 AMmetlx
the parallel line will go through point (8,-9)

y = kx + n

9x - 2y = 5

2y = 9x -5

y = (9/2)x - 5/2 <<< the first line

Parallel lines have the same koeficient k.

k in your case = 9/2

now you insert the coordinates of the point through which the parallel line will go through.

-9 = (9/2) * 8 + n

- 9 = 36 + n

n = -45

y = (9/2)x -45 - Jan 26th 2009, 09:36 AMPlato
Here is an easy way.

Any line parallel to $\displaystyle 9x-2y=5$ look $\displaystyle 9x-2y=K$.

To find $\displaystyle K$ use the point $\displaystyle x=8\;\&\;y=-9$: $\displaystyle 9({\color{red}8})-2({\color{red}-9})=({\color{red}90}) $

So your line is $\displaystyle 9x-2y=90$

Note there is a ‘sign’ error in the above reply.

This method minimizes those type of errors.