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Math Help - Determine an equation for this parabola

  1. #1
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    Determine an equation for this parabola

    A graph of a parabola has a line of symmetry X=3 and contains the points (1,0) and (4,-3) Determine an equation for this parabola.

    using y=a(X-h)^2+K

    -3 = a(4-1)^2 + 0
    -3 = -1/3(4-1)^2 + 0

    did i work this correctly?
    thanks
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Sxon View Post
    A graph of a parabola has a line of symmetry X=3 and contains the points (1,0) and (4,-3) Determine an equation for this parabola.

    using y=a(X-h)^2+K

    -3 = a(4-1)^2 + 0
    -3 = -1/3(4-1)^2 + 0

    did i work this correctly?
    thanks
    um, no

    our parabola is of the form y = a(x - 3)^2 + k

    since (1,0) is on the graph, we have

    0 = a(1 - 3)^2 + k .................(1)

    since (4,-3) is on the graph, we have

    -3 = a(4 - 3)^2 + k ................(2)


    thus we have two simultaneous equations with two unknowns. solve this system to find your parabola
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