A graph of a parabola has a line of symmetry X=3 and contains the points (1,0) and (4,-3) Determine an equation for this parabola.
using y=a(X-h)^2+K
-3 = a(4-1)^2 + 0
-3 = -1/3(4-1)^2 + 0
did i work this correctly?
thanks
A graph of a parabola has a line of symmetry X=3 and contains the points (1,0) and (4,-3) Determine an equation for this parabola.
using y=a(X-h)^2+K
-3 = a(4-1)^2 + 0
-3 = -1/3(4-1)^2 + 0
did i work this correctly?
thanks