# Graphing standard equation

• January 25th 2009, 06:00 PM
AlgebraicallyChallenged
Graphing standard equation
How do i graph a circle with a center of (-4-1) and a radius sqr rt of 46
• January 25th 2009, 06:41 PM
mr fantastic
Quote:

Originally Posted by AlgebraicallyChallenged
How do i graph a circle with a center of (-4-1) and a radius sqr rt of 46

Use the definition of a circle.

Maybe your real question is how to find the equation of this circle so that you can find its x- and y-intercepts ....?

In which case you need to recall the standard form $(x - h)^2 + (y - k)^2 = r^2$ where r is the radous and (h, k) are the coordinates of the centre.