To find h(0.5) substitute t=0.5 into the expression for h(t) ie. h(0.5)=- 16^0.5^2+45^0.5+200.A rock is thrown upwards from a height of 200 feet with an initial velocity of 45 feet/second. The height of the rock above the groundtseconds after being released is given by h(t)=- 16^t^2+45^t+200 Make a table of values ofh(t) and match the following:

Matching pairs

h(0.5)

- Select choice -228.7229.0226.0231.5218.5212.5216.5

h(1.0)

- Select choice -228.7229.0226.0231.5218.5212.5216.5

h(1.5)

- Select choice -228.7229.0226.0231.5218.5212.5216.5

h(2.0)

- Select choice -228.7229.0226.0231.5218.5212.5216.5

h(2.5)

Do the same with the other values.

The easiest way to do this is probably to try each pair of numbers and see which one gives numbers on either side of 12.The function f(x) =2^x^3-4^x+1 has the output value 12 for exactly one input value ofx. Between which of the following pairs of numbers does this input value ofxlie?