How would i find the x intercept of the following:
a) $\displaystyle y=-5$
b) $\displaystyle y=-3x+9$
c) $\displaystyle 2x+3y-6=0$
d) $\displaystyle x=-4$
Thanks guys!
To find the x-intercept, set y to 0.
a) This one has no x-intercept, y is always -5 so it never crosses the x axis (which is defined by y=0).
b) 0=-3x+9
3x=9
x=3
So the x intercept is (3,0) or just 3.
c) 2x+3(0)-6=0
2x-6=0
2x=6
x=3
Same answer as b).
d) x is always equal to -4 regardless of y, so the x intercept is (-4,0).
Hope that helps.
Depends on what t and d represent. I would assume that t stands for time and d stands for distance, in which case d would be you dependent variable (y).
y is always the variable that depends on the other one. For example if I had the equation p-3s-5=0, where p is the profit and s is the number of sales, well obviously my profit depends on the number of sales so p=y and s=x so I'd write p=3s+5.
Hope that all makes sense.