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Math Help - getting polar form

  1. #1
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    Question getting polar form

    i have the 2 end points on a pine
    a) (3, 58)
    b) (3, 44)

    i need to get polar form and the linear equation

    i know i have to use y=mx+b
    but how would i do that??
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  2. #2
    Super Member
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    Quote Originally Posted by lucifer_x View Post
    i have the 2 end points on a pine
    a) (3, 58)
    b) (3, 44)

    i need to get polar form and the linear equation

    i know i have to use y=mx+b
    but how would i do that??
    Your line is vertical, parallel to the y axis, and hence is undefined as far as  y = mx+c goes.

    The line has the equation:

     x = 3

    In polar coordinates  x = r\cos(\theta)

    Hence the furthest you can go is to say :  r\cos(\theta) = 3

    Hence  r = \frac{3}{\cos(\theta)}

    The line has length  58-44 , so this gives you the magnitude,  r = 14 :
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