# Math Help - getting polar form

1. ## getting polar form

i have the 2 end points on a pine
a) (3, 58)
b) (3, 44)

i need to get polar form and the linear equation

i know i have to use y=mx+b
but how would i do that??

2. Originally Posted by lucifer_x
i have the 2 end points on a pine
a) (3, 58)
b) (3, 44)

i need to get polar form and the linear equation

i know i have to use y=mx+b
but how would i do that??
Your line is vertical, parallel to the y axis, and hence is undefined as far as $y = mx+c$ goes.

The line has the equation:

$x = 3$

In polar coordinates $x = r\cos(\theta)$

Hence the furthest you can go is to say : $r\cos(\theta) = 3$

Hence $r = \frac{3}{\cos(\theta)}$

The line has length $58-44$, so this gives you the magnitude, $r = 14$: