i have the 2 end points on a pine

a) (3, 58)

b) (3, 44)

i need to get polar form and the linear equation

i know i have to use y=mx+b

but how would i do that??

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- Jan 20th 2009, 07:01 PMlucifer_xgetting polar form
i have the 2 end points on a pine

a) (3, 58)

b) (3, 44)

i need to get polar form and the linear equation

i know i have to use y=mx+b

but how would i do that?? - Jan 20th 2009, 07:27 PMMush
Your line is vertical, parallel to the y axis, and hence is undefined as far as $\displaystyle y = mx+c$ goes.

The line has the equation:

$\displaystyle x = 3 $

In polar coordinates $\displaystyle x = r\cos(\theta) $

Hence the furthest you can go is to say :$\displaystyle r\cos(\theta) = 3 $

Hence $\displaystyle r = \frac{3}{\cos(\theta)} $

The line has length $\displaystyle 58-44 $, so this gives you the magnitude, $\displaystyle r = 14 $: