Thread: Coin problem

The value (in cents) of the change in a purse that contains twice as many nickels as pennies, four more dimes than nickels, and as many quarters as dimes and nickels combined; p = number of pennies?

Hello tmac11522

Originally Posted by tmac11522

The value (in cents) of the change in a purse that contains twice as many nickels as pennies,

Originally Posted by tmac11522

four more dimes than nickels, and as many quarters as dimes and nickels combined; p = number of pennies?

Number of pennies = . Each penny is worth one cent. So the value of the pennies = cents

Number of nickels = twice as many as number of pennies = . Each nickel is worth 5 cents. So the value of the nickels = cents

Number of dimes = four more than the number of nickels = . Each dime is worth 10 cents. So the value of the dimes = ??? cents.

Number of quarters = number of dimes plus number of nickels = ??. Each quarter is worth 25 cents, so the value of the quarters is ??? cents.

Add together all four value totals; remove the brackets and simplify the result. You'll then arrive at an expression like , where and are two whole numbers. That will be your final answer, if you don't have any more information.

Can you complete it now?

Grandad