Math Help - Precalc question

again using this "rule of four", it says
Find all real numbers such that
2^x=x^2
lol. i got no idea, division maybe? do 2^x/x^2, but after that, i dont know what else to do. anyone?

Originally Posted by robdarftw

again using this "rule of four", it says
Find all real numbers such that
2^x=x^2
lol. i got no idea, division maybe? do 2^x/x^2, but after that, i dont know what else to do. anyone?

what is this rule of four you speak of?

by inspection, x = 2 and x = 4 are solutions. there is one more between 0 and -1. i do not see a nice way of getting its value though. i guess you can use some approximation method, like the Newton-Raphson method

lol teh rule of four is apparently just writing things oout graphically, numerically, algebraicaly, and verbally. And I graphed the solution and found the intersection point, which was -0.77 approx.
thnx for the help though

Originally Posted by robdarftw

lol teh rule of four is apparently just writing things oout graphically, numerically, algebraicaly, and verbally. And I graphed the solution and found the intersection point, which was -0.77 approx.
thnx for the help though

yup, the last answer is around that. i used a graph to realize this also