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Math Help - Precalc question

  1. #1
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    Precalc question

    again using this "rule of four", it says
    Find all real numbers such that
    2^x=x^2
    lol. i got no idea, division maybe? do 2^x/x^2, but after that, i dont know what else to do. anyone?
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by robdarftw View Post
    again using this "rule of four", it says
    Find all real numbers such that
    2^x=x^2
    lol. i got no idea, division maybe? do 2^x/x^2, but after that, i dont know what else to do. anyone?
    what is this rule of four you speak of?

    by inspection, x = 2 and x = 4 are solutions. there is one more between 0 and -1. i do not see a nice way of getting its value though. i guess you can use some approximation method, like the Newton-Raphson method
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  3. #3
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    lol teh rule of four is apparently just writing things oout graphically, numerically, algebraicaly, and verbally. And I graphed the solution and found the intersection point, which was -0.77 approx.
    thnx for the help though
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by robdarftw View Post
    lol teh rule of four is apparently just writing things oout graphically, numerically, algebraicaly, and verbally. And I graphed the solution and found the intersection point, which was -0.77 approx.
    thnx for the help though
    yup, the last answer is around that. i used a graph to realize this also
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