I'm currently reviewing for a Calculas exam I have soon, and although there are a few review questions I can't seem to get, I'll stick with this one. (By the way, if it is super simple, excuse me, I really CANT do calculas.)
Question: Determine the equation of the line perpindicular to f(x)=1/2e^x+1 at its y-intercept.
What I did was found the dervitive, which I got to be the same thing (f'(x)=1/2e^x+1) although it could be wrong. Only problem is that I have no clue what to do after that. The answer is suppose to be y=e/2 x+e/2
Any help is appreciated!
As written by HallsofIvy the slope of the tangent line to the graph is the derivative evaluated at x= 0 which is .
This means that a direction vector of the tangent has coordinates (1,e/2).
You have to find the coordinates of a vector perpendicular to this one.