Find (f o g)´ at x = 4 if f(u)=u^3 - 5 and u= g(x)= 3(x^(1/2)) I got (f o g)´ = 40.5(x^1/2) Can someone tell me if I did it right?
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Originally Posted by h4hv4hd4si4n Find (f o g)´ at x = 4 if f(u)=u^3 - 5 and u= g(x)= 3(x^(1/2)) I got (f o g)´ = 40.5(x^1/2) Can someone tell me if I did it right? What you mean by (f o g)´?
That is the correct answer. (f o g) = (3(x^1/2))^3 - 5 = 27x^3/2 - 5 (f o g)´ = (81/2) x^1/2 @Mush: The derivative of the function g composed into the function of f.
Originally Posted by MacstersUndead That is the correct answer. (f o g) = (3(x^1/2))^3 - 5 = 27x^3/2 - 5 (f o g)´ = (81/2) x^1/2 @Mush: The derivative of the function g composed into the function of f. Ah. Yes, then the OP is correct. Remember to implement the condition that x=4.
thanks for checking it out for me
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