Thread: Ellipse Query

Hello, can anybody help me write this Ellipse equation given to me
"x^2 + 25y^2 -2x + 150y + 201 = 0" in its standard Ellipse form, which i believe is this..

Originally Posted by 14041471

write this Ellipse equation given to me
"x^2 + 25y^2 -2x + 150y + 201 = 0" in its standard Ellipse form

Group the x- and y-terms together, with the stray constant term moved to the othe side of the equation:

. . . . .

Then complete the two squares, starting by:

. . . . .


If you get stuck in the process, please study one or more online lessons to remind yourself of how it works. If you grind to a halt, please reply showing how far you have gotten.

Thank you!

I tried to finish is myself and this was the outcome
(x-2) - 25(y+3) -201
=(x-2)^2/0 - (y+3)^2/-8.04

is that correct?

Originally Posted by 14041471

I tried to finish is myself and this was the outcome
(x-2) - 25(y+3) -201

I'm sorry, but I don't understand how you arrived at this expression...? You should, at every stage, have an equation.

Instead, try starting with the equation I gave you, and follow the steps in the completing-the-square process to fill in the empty spaces I'd left for you. Then divide through by whatever number you end up with on the righ-hand (non-variable) side of the equation to get "=1", and you're done!

Have fun!

Hello, can anybody help me write this Ellipse equation given to me
"x^2 + 25y^2 -2x + 150y + 201 = 0" in its standard Ellipse form, which i believe is this..

this is the answer:
((x-1)^2/25)+((y+3)^2/1)=1