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Math Help - Ellipse Query

  1. #1
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    Ellipse Query

    Hello, can anybody help me write this Ellipse equation given to me
    "x^2 + 25y^2 -2x + 150y + 201 = 0" in its standard Ellipse form, which i believe is this..
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  2. #2
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    Quote Originally Posted by 14041471 View Post
    write this Ellipse equation given to me
    "x^2 + 25y^2 -2x + 150y + 201 = 0" in its standard Ellipse form
    Group the x- and y-terms together, with the stray constant term moved to the othe side of the equation:

    . . . . . x^2\, -\, 2x\, +\, 25y^2\, +\, 150y\, =\, -201

    Then complete the two squares, starting by:

    . . . . . \left(x^2\, -\, 2x\, +\, \mbox{ }\right)\, +\, 25\left(y^2\, +\, 6y\, +\, \mbox{ }\right)\, =\, -201


    If you get stuck in the process, please study one or more online lessons to remind yourself of how it works. If you grind to a halt, please reply showing how far you have gotten.

    Thank you!
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  3. #3
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    thanks

    I tried to finish is myself and this was the outcome
    (x-2) - 25(y+3) -201
    =(x-2)^2/0 - (y+3)^2/-8.04

    is that correct?
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  4. #4
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    Quote Originally Posted by 14041471 View Post
    I tried to finish is myself and this was the outcome
    (x-2) - 25(y+3) -201
    I'm sorry, but I don't understand how you arrived at this expression...? You should, at every stage, have an equation.

    Instead, try starting with the equation I gave you, and follow the steps in the completing-the-square process to fill in the empty spaces I'd left for you. Then divide through by whatever number you end up with on the righ-hand (non-variable) side of the equation to get "=1", and you're done!

    Have fun!
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  5. #5
    Junior Member ursa's Avatar
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    Hello, can anybody help me write this Ellipse equation given to me
    "x^2 + 25y^2 -2x + 150y + 201 = 0" in its standard Ellipse form, which i believe is this..
    this is the answer:
    ((x-1)^2/25)+((y+3)^2/1)=1
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