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Math Help - Conics

  1. #1
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    Conics

    (1/16)(x + 2)^2 + (1/9)(y - 5)^2 = 1

    I was given this Ellipse in 'standard form'

    How can I find the Foci and Length of Major axis?
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  2. #2
    MHF Contributor
    Joined
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    Talking

    Quote Originally Posted by 14041471 View Post
    (1/16)(x + 2)^2 + (1/9)(y - 5)^2 = 1
    Compare the above to the formula they gave you, which probably looks like the following:

    . . . . . \frac{(x\, -\, h)^2}{a^2}\, +\, \frac{(y\, -\, k)^2}{b^2}\, =\, 1

    How do h, k, a, and b relate to the foci and the axes?

    Have fun!
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