1. ## Conics

(1/16)(x + 2)^2 + (1/9)(y - 5)^2 = 1

I was given this Ellipse in 'standard form'

How can I find the Foci and Length of Major axis?

2. Originally Posted by 14041471
(1/16)(x + 2)^2 + (1/9)(y - 5)^2 = 1
Compare the above to the formula they gave you, which probably looks like the following:

. . . . . $\frac{(x\, -\, h)^2}{a^2}\, +\, \frac{(y\, -\, k)^2}{b^2}\, =\, 1$

How do h, k, a, and b relate to the foci and the axes?

Have fun!