# Solving logs and rubberband transformation ect.

• Jan 14th 2009, 08:12 PM
lic2kill
Solving logs and rubberband transformation ect.
First of all, can this be reduced at all? I think you do natural log to cancel out the e but, not sure where to go from there :|
http://www.texify.com/img/%5CLARGE%5...7Be%5Ex%7D.gif

Second, Solve for all real values of x:
(x-2)log x = 7x - 14

Rubber Band Transformation?
y=3x²-2x+5
R: (x,y) --> (1/5(x), 2y + 4)

Solve for all real values of r;
http://www.texify.com/img/%5CLARGE%5...2%2Br-6%7D.gif

Studying for a good ol final, stuff isn't clicking right now. Thanks

• Jan 14th 2009, 09:16 PM
lic2kill
Stuck at (x^(n-2))-7x+14=0 not even sure if that's right
• Jan 15th 2009, 08:23 AM
Soroban
Hello, lic2kill!

Quote:

Solve for all real values of $r\!:\;\;\frac{1}{2r^2-7t+6} \:=\:\frac{1}{2r^2 + r - 6}$

Note that we have: . $\frac{1}{(r-2)(2r-3)} \:=\:\frac{1}{(r+2)(2r-3)}$
. Hence: . $r \:\neq \:\pm2,\: \frac{3}{2}$

Multiply by $(r-2)(r+2)(2r-3)\!:\;\;r + 2 \:=\:r - 2 \quad\Rightarrow\quad 0 \:=\:\text{-}4$ .??

There are no solutions.

• Jan 15th 2009, 01:26 PM
lic2kill
I had my final today, there was a problem just like that one, and I came with no solution too, yay, thanks for answering

That log one has been bothering me though, I ended up graphing it and finding two zeros, but not sure if that's right....