Polynomial Shift

**amma0913** · January 13th 2009, 05:47 PM

Suppose P(x) = anxn + an-1xn-1+an-2xn-2+…+a1x1+a0 is any polynomial of degree 1 or higher with real coefficients. Show that there must exist a real number k so that if we create the new polynomial Q(x) = P(x-k), then Q(x) = bnxn + bn-2xn-2 + … + b1x1 + b0 meaning that the shift has caused the new polynomial to lose its x^(n-1) term.

I know it has something to do with the significance of the 2nd coefficient polynomial, but I get lost after that. any help appreciated.

**NonCommAlg** · January 13th 2009, 09:00 PM

Originally Posted by amma0913

Suppose $P(x) = a_nx^n + a_{n-1}x^{n-1}+a_{n-2}x^{n-2} + \cdots +a_1x + a_0$ is any polynomial of degree 1 or higher with real coefficients. Show that there must exist a real number $k$ so that if we

create the new polynomial $Q(x) = P(x-k),$ then $Q(x) = b_nx^n + b_{n-2}x^{n-2} + \cdots + b_1x + b_0$ meaning that the shift has caused the new polynomial to lose its $x^{n-1}$ term.

I know it has something to do with the significance of the 2nd coefficient polynomial, but I get lost after that. any help appreciated.

Hint: $k=\frac{a_{n-1}}{na_n}.$

Thread: Polynomial Shift

LinkBack

Thread Tools

Display

Polynomial Shift

Similar Math Help Forum Discussions

Best way to shift x^2 -2x -3 to the right by 1

phase shift

Phase Shift

phase shift

Phase shift??

Search Tags