Hi, my question is :
Let n be a positive integer. Find all real numbers x such that
I find that there is no such REAL number.
Does someone find a different answer?
Well a pretty obvious solution from inspection is that if n is even, then x = 0 is a real number solution. But I'll do the working just to see if any others lurk:
Get all x terms on LHS and non-x terms on RHS
Hence for any positive integer.
For
Hence the equation has a real number solution for all even values of n. And that solution is . 0 is a real number.