Thank You!!!
If you start with a ray pointing along the x-axis $\displaystyle \theta = 0$, if you rotate the ray $\displaystyle \theta = \frac{\pi}{3}$, then move aong the ray 4 unit (this is v), this determines a point. From this, you can draw a triangle in the first quadrant. The vector you seek is
$\displaystyle <|\,v\,|\, \cos \theta,\; |\,v\,| \sin \theta >$