Thank You!!!

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- Jan 13th 2009, 11:12 AMqbkr21Vector and Angles
Thank You!!!

- Jan 13th 2009, 02:59 PMJester
If you start with a ray pointing along the x-axis $\displaystyle \theta = 0$, if you rotate the ray $\displaystyle \theta = \frac{\pi}{3}$, then move aong the ray 4 unit (this is v), this determines a point. From this, you can draw a triangle in the first quadrant. The vector you seek is

$\displaystyle <|\,v\,|\, \cos \theta,\; |\,v\,| \sin \theta >$