Hello; I currently working on absolute values and was doing good until I now.
Can anyone please explain to me, why; the absolute value of the square route of 2 -5 is 5- the square route of 2?
Thanks a bunch
Carolyn
By definition $\displaystyle \left| a \right| = \left\{ {\begin{array}{*{20}c}
{a,} & {0 \leqslant a} \\ { - a,} & {a < 0} \\ \end{array} } \right.$.
Now $\displaystyle \sqrt 2 - 5 < 0\;\text{ so }\;\left| {\sqrt 2 - 5} \right| = - \left( {\sqrt 2 - 5} \right) = 5 - \sqrt 2 .
$
I'm finding all of this quite helpful. One more question about this sight (this is my first time using it). Can someone please explain to me how to make math symbols so I don't have to spell out words such as; "square root and absolute value". It would make future postings easier to read. I tried unsuccessfully locating a "cheat sheet" if you will.
Regards
Carolyn