From beginning: Derivative of the function is
Maximum height is: . The average velocity from beginning . Average velocity is:
So in t_0 = 2,5, the average velocity is:
If a ball is thrown into the air with avelocity of 80ft/s, its height in feet after t seconds is given by y= 80t-16t^2 . find its averge velocity from the time its thrown to the time it reaches its maximan height.
here is what i did
first i took the dervative of the function and equalled it to zero. i got t= 2.5.
then i calculated the average velocity i got 32 where it should be 40. i guess that i made a mistake while calculating the average velocity. can someone help me from there.
thanks in advance!!
Try to realise this situation. You product 300 toys per day. What's the average (in hours)? that is 300/24 = 12.5. So you procuct 12.5 toys per hour. Now I have a function, which is modelling the height in particular time. So the average is:
Numerator : Height
Denominator : quantity (time)