The second period College Algebra class of 33 students could do n problems in x hours. If 3 students were absent, how long would it take to do 100 problems?

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- October 23rd 2006, 08:35 PMrobinpatrick(workers)x(rate)x(time) = jobs problem
The second period College Algebra class of 33 students could do n problems in x hours. If 3 students were absent, how long would it take to do 100 problems?

- October 24th 2006, 05:58 AMCaptainBlack
The average student does n/(x.33) problems per hour (total of n problems done in: 33 times x hours of student effort).

Therefore to do 100 problems with 30 students would take h hours where:

100/(h.30) = n/(x.33),

or rearranging:

h = 100.x.33/n = 3300.x/n

RonL