The second period College Algebra class of 33 students could do n problems in x hours. If 3 students were absent, how long would it take to do 100 problems?

Printable View

- Oct 23rd 2006, 07:35 PMrobinpatrick(workers)x(rate)x(time) = jobs problem
The second period College Algebra class of 33 students could do n problems in x hours. If 3 students were absent, how long would it take to do 100 problems?

- Oct 24th 2006, 04:58 AMCaptainBlack
The average student does n/(x.33) problems per hour (total of n problems done in: 33 times x hours of student effort).

Therefore to do 100 problems with 30 students would take h hours where:

100/(h.30) = n/(x.33),

or rearranging:

h = 100.x.33/n = 3300.x/n

RonL