Originally Posted by
ThePerfectHacker 1)The square root needs to be non-negative.
Thus, $\displaystyle \sqrt{-x}$ for $\displaystyle -x\geq 0$ thus, $\displaystyle x\leq 0$.
2)The numerator cannot be zero.
$\displaystyle x^3+2x^2-3x=0$
$\displaystyle x(x^2+2x-3)=0$
$\displaystyle x(x+3)(x-1)=0$
Thus,
$\displaystyle x\not = 0,1,-3$.
Since $\displaystyle x\leq 0$ the only one of those that works is $\displaystyle x=-3$ thus,
$\displaystyle x\leq 0 \mbox{ and } x\not = -3$
Thus,
$\displaystyle (-\infty,-3)\cup (-3,0]$
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[Note for you, for anyone interested in anything I have to say].
These domain seem not be be well-defined, because to definied a function you need to create a domain and co-domain which you did not do here. Thus, how can you find a domain?