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Math Help - hyperbolas

  1. #1
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    hyperbolas

    Please help me to put this equation
    > "36x^2 - 100y^2 - 72x + 400y = 3928"
    In the standard Hyperbola form >
    All I know is that I need to start by "Factoring" the original equation, but I'm not to sure even how to do that

    Thanks
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  2. #2
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    Hi

    Here is the beginning

    36x^2 - 100y^2 - 72x + 400y = 3928

    36(x^2 - 2x) - 100(y^2 - 4y) = 3928

    36((x-1)^2 - 1) - 100((y-2)^2 - 4) = 3928

    36(x-1)^2 - 100(y-2)^2 = 3928 + 36 - 400
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  3. #3
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    hyperbola standard form

    I had to put this equation > 36x^2 - 100y^2 - 72x + 400y = 3928
    in this form
    With Help I got to this stage
    36(x-1)^2 - 100(y-2)^2 = 3928 + 36 - 400
    and then
    36(x-1)^2/99 - 100(y-2)^2/35.64 but the simple form has a^2 and b^2 and I cant find the square root of 99 and 35.64 which leads me to beleive that im wrong, please help.
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  4. #4
    A riddle wrapped in an enigma
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    Quote Originally Posted by 14041471 View Post
    I had to put this equation > 36x^2 - 100y^2 - 72x + 400y = 3928
    in this form
    With Help I got to this stage
    36(x-1)^2 - 100(y-2)^2 = 3928 + 36 - 400
    and then
    36(x-1)^2/99 - 100(y-2)^2/35.64 but the simple form has a^2 and b^2 and I cant find the square root of 99 and 35.64 which leads me to beleive that im wrong, please help.
    Why can't you take the square root of those numbers? They're both positive. They're just not perfect squares.
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  5. #5
    A riddle wrapped in an enigma
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    Quote Originally Posted by 14041471 View Post
    I had to put this equation > 36x^2 - 100y^2 - 72x + 400y = 3928
    in this form
    With Help I got to this stage
    36(x-1)^2 - 100(y-2)^2 = 3928 + 36 - 400
    and then
    36(x-1)^2/99 - 100(y-2)^2/35.64 but the simple form has a^2 and b^2 and I cant find the square root of 99 and 35.64 which leads me to beleive that im wrong, please help.
    I believe this is what you should have:

    \frac{(x-1)^2}{99}-\frac{(y-2)^2}{35.64}=1
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