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Math Help - World of Logs Rules

  1. #1
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    World of Logs Rules

    Write as the sum and /or difference of logs. Express powers as factors.

    16. In (x+8)(x-9)^3/2 / ((x-4)^4 , x>9

    A. 3/2In(x+8)+3/2In(x-9)-6In(x-4)
    B. In(x+8)+In(x-9)+In3-12In(x-4)-In2
    C.3/2In(x^2+17x-72)-6In(x-4)
    D.3In(x+8)-2In(x-9)-6In(x-4)
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  2. #2
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    Quote Originally Posted by magentarita View Post
    Write as the sum and /or difference of logs. Express powers as factors.

    16. In (x+8)(x-9)^3/2 / ((x-4)^4 , x>9

    A. 3/2In(x+8)+3/2In(x-9)-6In(x-4)
    B. In(x+8)+In(x-9)+In3-12In(x-4)-In2
    C.3/2In(x^2+17x-72)-6In(x-4)
    D.3In(x+8)-2In(x-9)-6In(x-4)
     \ln{|\frac{(x+8)(x+9)^{\frac{3}{2}}}{(x-4)^4}|}

    Is that what it is supposed to look like?

    If so:

     \ln{|(x+8)(x+9)^{\frac{3}{2}}|}-\ln{|(x-4)^4|}

     \ln{|(x+8)|}+\ln{|(x+9)^{\frac{3}{2}}|}-\ln{|(x-4)^4|}

     \ln{|(x+8)|}+\frac{3}{2}\ln{|(x+9)|}-4\ln{|(x-4)|}
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  3. #3
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    your answer...

    Quote Originally Posted by Mush View Post
     \ln{|\frac{(x+8)(x+9)^{\frac{3}{2}}}{(x-4)^4}|}

    Is that what it is supposed to look like?

    If so:

     \ln{|(x+8)(x+9)^{\frac{3}{2}}|}-\ln{|(x-4)^4|}

     \ln{|(x+8)|}+\ln{|(x+9)^{\frac{3}{2}}|}-\ln{|(x-4)^4|}

     \ln{|(x+8)|}+\frac{3}{2}\ln{|(x+9)|}-4\ln{|(x-4)|}
    Your answer is which choice?
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