The questions asks to find the point that divides the interval AB ( A(-7, 5), B(3, 1) ) into the ratio 3:1

I'm looking at the answer but I can't work out why they changed 3:1 to 3:-1 and therefore get a different answer to me

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- Oct 22nd 2006, 10:59 PMchanceyMidpoint formula question
The questions asks to find the point that divides the interval AB ( A(-7, 5), B(3, 1) ) into the ratio 3:1

I'm looking at the answer but I can't work out why they changed 3:1 to 3:-1 and therefore get a different answer to me - Oct 23rd 2006, 01:36 AMearboth
- Oct 23rd 2006, 07:08 AMSoroban
Hello, chancey!

You could baby-talk your way through this one . . .

Quote:

Find the point that divides the line segment into the ratio

given:

We want a point which is the distance from to

. . . . . . . . . . . . . . . .

. .

To go from to , we'd move:

To go three-fourths the distance, we'd move:

Hence, is: .

Of course, this is basically Earboth's solution.