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Math Help - Complex numbers, very easy but I just can't see it!

  1. #1
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    Complex numbers, very easy but I just can't see it!

    How would I possibly evaluate this? It looks as simplified as it can get.




    Thanks a ton!
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  2. #2
    Moo
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    Multiply both numerator and denominator by the denominator's conjugate.

    Remember, the conjugate of a complex number a+ib is a-ib.

    and (a+ib)(a-ib)=aČ+bČ, which is a real number and this is the reason for which we make this operation.
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  3. #3
    Newbie DaveDammit's Avatar
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    Yes, remember that you just multiply by the conjugate of the denominator and FOIL. Also remember that i^2 is equal to -1.
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