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Math Help - Series and sequence question

  1. #1
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    Question Series and sequence question

    how would this work out

    Solve: ln(e) (-.3675)
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  2. #2
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    Quote Originally Posted by lucifer_x View Post
    how would this work out

    Solve: ln(e) (-.3675)
    I'm sorry, is that

     ln \left( e^{-.3675} \right) or  ln (e) \times (-.3675) ?
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    Quote Originally Posted by lucifer_x View Post
    Note that \ln\left(e\right)=1.

    So what do you think the answer is now?
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  5. #5
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    is the ln(e)

    cuz the e is suppose to be the under root of ln
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    Quote Originally Posted by lucifer_x View Post
    is the ln(e)

    cuz the e is suppose to be the under root of ln
    What you are posting makes no sense.

    Please post the question so that it can be clearly understood.
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  7. #7
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    ok look

    LOG(e) (-.3675)


    the e is like the lower part of log
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  8. #8
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    Quote Originally Posted by lucifer_x View Post
    is the ln(e)

    cuz the e is suppose to be the under root of ln
    Quote Originally Posted by lucifer_x View Post
    ok look

    LOG(e) (-.3675)

    the e is like the lower part of log
    If you mean log_e (-0.3675) then:

    1. There is no real value.

    2. Talk about "under the root" is confusing and misleading. The correct term is "base", as in "The base of the log is e".

    3. What is meant to be assumed by the multiplication symbol here:
    Quote Originally Posted by lucifer_x View Post
    ln(e) \times (-.3675)
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  9. #9
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    yes i know i misread my homework and put ln instead of the log, that was my bad but everyone makes mistakes.

    but yes that was the right question

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  10. #10
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    Quote Originally Posted by lucifer_x View Post
    yes i know i misread my homework and put ln instead of the log, that was my bad but everyone makes mistakes.

    but yes that was the right question

    I'm not talking about ln versus log or whatever. I'm talking about your incorrect use of the multiplication symbol and your incorrect use of the expression "under the root".

    And as I have already said, the expression has no real value.

    Are you attempting to find the non-real value? If so, then you should have said so in the first place. Otherwise, there's nothing more to be said.
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  11. #11
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    i really dont know what my teacher wants all he put was

    solve

    and thats it, i will probably put no real values
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