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Math Help - Question about parameters in square root function (Grade 11)

  1. #1
    s3a
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    Question about parameters in square root function (Grade 11)

    I get g(x)=sqrt(-(x+1)) and the solution guide says g(x)=sqrt(-(x-1)). Is my answer wrong or is the solution guide wrong?
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  2. #2
    MHF Contributor red_dog's Avatar
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    After the first transformation: f_1(x)=-\sqrt{x}
    After the second transformation: g(x)=-\sqrt{x-1}
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  3. #3
    s3a
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    If the negative is outside the square root, you're changing the a parameter (vertical change). Both the solution guide and my answer has the negative inside the square root. In high school, I know that you can't have a negative numerical value in a square root but the letters (unknowns) can also be negative which could result in a positive value. But, I still need help understanding the minor difference in answers between me and my solutions guide.
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  4. #4
    A riddle wrapped in an enigma
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    Quote Originally Posted by s3a View Post
    I get g(x)=sqrt(-(x+1)) and the solution guide says g(x)=sqrt(-(x-1)). Is my answer wrong or is the solution guide wrong?
    Hello s3a,

    f(x)=\sqrt{x} reflected about the y-axis will yield

    f_1(x)=\sqrt{-x}.

    Then, if you translate (slide) 1 unit to the right, you end up with

    \boxed{g(x)=\sqrt{-x+1}=\sqrt{-(x-1)}}, which is what your answer key says.

    Your solution, g(x)=\sqrt{-(x+1)} will translate the graph 1 unit to the left.
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