1. ## circle formula

4x^2 + 8y^2 - 12x + 16y + 18 = 0
4 (x^2 - 3x + (3/2)^2) + 8 (y^2 + 2y +1) = -18 + 9 + 8
4 (x-(3/2))^2 + 8 (y + 1)^2 = -1

What do I do then?
Thank you

2. Originally Posted by oceanmd
4x^2 + 8y^2 - 12x + 16y + 18 = 0
4 (x^2 - 3x + (3/2)^2) + 8 (y^2 + 2y +1) = -18 + 9 + 8
4 (x-(3/2))^2 + 8 (y + 1)^2 = -1

What do I do then?
Thank you
There is a typo in the original question since there's clearly no coordinate (x, y) that satisifes $4x^2 + 8y^2 - 12x + 16y + 18 = 0$.

Note: The fact that you think it's meant to be a circle means that the coefficient of x^2 and y^2 has to be the same ..... This is NOT currently the case.

3. ## Thank you

Thank you very mucch

4. What is correct is that the "graph" of that relation is the empty set.