Write this expression using only natural logarithms: log (x-y) ----> (1/5 is the base) 1/5 Thanks for any help!
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Originally Posted by live_laugh_luv27 Write this expression using only natural logarithms: log (x-y) ----> (1/5 is the base) 1/5 Thanks for any help! use the change of base formula ... $\displaystyle \log_b{a} = \frac{\ln{a}}{\ln{b}}$
ok , and i got ln(x-y) / ln(1/5). Would I leave this as the answer, or would I distribute to get lnx - lny / ln1 - ln5 ??
review your log properties ... first off, $\displaystyle \ln(x-y) \neq \ln{x} - \ln{y}$ ,and $\displaystyle \ln\left(\frac{1}{5}\right) = \ln{1} - \ln{5} = 0 - \ln{5} = -\ln{5}$
so, ln(x-y) can't be reduced?
no ... you're stuck with it.
ok thanks for the help
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