Write this expression using only natural logarithms:

log (x-y) ----> (1/5 is the base)

1/5

Thanks for any help!

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- Dec 22nd 2008, 01:37 PMlive_laugh_luv27Natural logarithms
Write this expression using only natural logarithms:

log (x-y) ----> (1/5 is the base)

1/5

Thanks for any help! - Dec 22nd 2008, 01:53 PMskeeter
- Dec 22nd 2008, 01:56 PMlive_laugh_luv27
ok , and i got ln(x-y) / ln(1/5). Would I leave this as the answer, or would I distribute to get lnx - lny / ln1 - ln5 ??

- Dec 22nd 2008, 02:00 PMskeeter
review your log properties ...

first off, $\displaystyle \ln(x-y) \neq \ln{x} - \ln{y}$ ,and

$\displaystyle \ln\left(\frac{1}{5}\right) = \ln{1} - \ln{5} = 0 - \ln{5} = -\ln{5}$ - Dec 22nd 2008, 02:10 PMlive_laugh_luv27
so, ln(x-y) can't be reduced?

- Dec 22nd 2008, 02:12 PMskeeter
no ... you're stuck with it.

- Dec 22nd 2008, 02:15 PMlive_laugh_luv27
ok thanks for the help :)