The domain of the function f(x)= 1-(2,+infinity) 2-all reals 3-(-infinity,-2)U(2,+infinity) 4-(-2,2) 5-(-infinity,-2)U(-2,+infinity) ============================ I try to solve this question : 4+x2>0 x2>-4 x>√-4 The square root is not defined for negative numbers.
Last edited by Diligent_Learner; December 18th 2008 at 12:14 PM.
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Is it possible for ?
Originally Posted by Plato Is it possible for ? I don't understand your question..Can you clarify your idea??
Are the any values of which gives ? If not, then the domain is all real numbers.
Originally Posted by Plato Are the any values of which gives ? If not, then the domain is all real numbers. we don't have any value of x because the square root for negative number is not defined
Is this true, for all , ? If that is true add 4 to both sides, . Therefore, is defined for all . Therefore, the domain of the function is all .
Originally Posted by Plato Is this true, for all , ? If that is true add 4 to both sides, . Therefore, is defined for all . Therefore, the domain of the function is all . Thank you very much I understand your idea.. If I want to obtain the range of the following function What I must do?? are there any steps to find range of any function ?and also the domain f(x)=
Originally Posted by Diligent_Learner Thank you very much I understand your idea.. If I want to obtain the range of the following function What I must do?? are there any steps to find range of any function ?and also the domain f(x)= To find the domain, To find the range, Therefore,
Originally Posted by masters To find the domain, To find the range, Therefore, Thank you very much .. I understand from your solution that: If i want to find the range : I should substitute the values of x that included into the domain into function and then I notice the the y values that the function will take..
Last edited by Diligent_Learner; December 19th 2008 at 01:42 PM.
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