I cant awnser both these questions, I'm unsure how to factor a quadratic Function. I think it needs to be in this form (x+/-...)(x+/-...)

1* Find the factored form of y = 2x^2 + 6x + 4

2*Find the factored form of y = x^2 + 4

2. 1. $2x^2 + 6x + 4$

Take out a common factor of 2

$\Rightarrow 2(x^2 + 3x + 2)$

Factorise:

$\Rightarrow 2(x + 2)(x + 1)$

The two numbers need to sum to the coefficient of x and multiply to the constant term in the expanded form of the quadratic.

2. $x^2 + 4$ cannot be factorised.

3. The following are the awnser choises i have for question 1.
2(x - 1)(x - 2)
(x + 1)(x + 2)
2(x - (-1))(x - (-2)) (I believe it's this one, am i correct?)
(x - (-1))(x - (-2))

The following are the awnser choises i have for question 2
(2x - i)(2x + i)
(x - 2)(x - (-2))
(x - 2i)(x - (-2i))
(x - 0)(x - 4)

4. Yes for Q1.

I didn't realise that complex numbers were involved here.

$x^2 + 4$ can be factorised as $(x + 2i)(x - 2i)$. (the third option)