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Math Help - Log equation is this correct?

  1. #1
    Junior Member
    Joined
    Dec 2008
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    32

    Log equation is this correct?

    10^(1-x) = 6 ^(x)


    I got:

    log10 / log6 + log10 = x
    or x = .562
    Last edited by needhelp75; December 17th 2008 at 12:14 AM.
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  2. #2
    Member
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    Dec 2008
    From
    Auckland, New Zealand
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    189
    10^{1-x} = 6^x

    \Rightarrow \frac{10^1}{10^x} = 6^x

    \Rightarrow 10 = 6^x \times 10^x

    \Rightarrow 10 = 60^x

    \Rightarrow x\ln60 = \ln 10

    \Rightarrow x = \frac{\ln 10}{\ln60} = 0.5624
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