So here's the problem: passes through (-2,2), parallel to graph of -2x + y = 4. Then I graph the line that satisfies the condition, but what I really need to know is just how to figure out the slope.

Exams tomorrow... please help me!

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- Dec 16th 2008, 08:28 AMkiwifruitParallel/Perpendicular Lines
So here's the problem: passes through (-2,2), parallel to graph of -2x + y = 4. Then I graph the line that satisfies the condition, but what I really need to know is just how to figure out the slope.

Exams tomorrow... please help me! - Dec 16th 2008, 08:41 AMPlato
- Dec 16th 2008, 08:45 AMChris L T521
When lines are parallel, they have the same slope. [i.e. if the slope of one line is $\displaystyle m=a$ then line two has a slope of $\displaystyle m_{\parallel}=a$

When lines are perpendicular, its a little different. If line one has a slope of $\displaystyle m=a$, then line two has a slope of $\displaystyle m_{\bot}=-\frac{1}{a}$