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Math Help - parallel equation to the line

  1. #1
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    Post parallel equation to the line

    help...

    A line has equation 3x + 2y = 6. Find the equation of the line parallel to this which passes through the point (2,10)

    i know when someone tells me this ill feel so stupid
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  2. #2
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    3x + 2y = 6
    2y = -3x + 6
    y = -3/2x + 3
    The gradient of the parallel line is -3/2

    Substitute (2,10) into y = -3/2x + c and find c

    10 = -3/2(2) + c
    10 = -3 + c
    c = 13

    Therefore the equation of the line is y = -3/2x + 13
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  3. #3
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    cheers matey
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  4. #4
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    Wink

    A line has equation 3x + 2y = 6. Find the equation of the line parallel to this which passes through the point (2,10)
    Okay, first you need to "solve" for "y".

    3x + 2y = 6

    2y = -3x + 6

    y = -(3/2)x + 3

    Now, since parallel lines have the same slope, you can set up your new equation, with the new points, using the same slope.

    y - y1 = m(x - x1)

    y - 10 = -3/2(x - 2

    Again, solve for "y"

    y - 10 = -3/2(x - 2

    y - 10 = -3/2x + 3

    y = -(3/2)x + 13 (<==ANSWER!!) :-)
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