# parallel equation to the line

• Dec 16th 2008, 07:22 AM
RubbishAtMaths
parallel equation to the line
help...

A line has equation 3x + 2y = 6. Find the equation of the line parallel to this which passes through the point (2,10)

i know when someone tells me this ill feel so stupid (Wondering)
• Dec 16th 2008, 07:33 AM
tester85
3x + 2y = 6
2y = -3x + 6
y = -3/2x + 3
The gradient of the parallel line is -3/2

Substitute (2,10) into y = -3/2x + c and find c

10 = -3/2(2) + c
10 = -3 + c
c = 13

Therefore the equation of the line is y = -3/2x + 13
• Dec 16th 2008, 07:36 AM
RubbishAtMaths
(Rofl)

cheers matey
• Dec 16th 2008, 07:37 AM
Tall Jessica
Quote:

A line has equation 3x + 2y = 6. Find the equation of the line parallel to this which passes through the point (2,10)
Okay, first you need to "solve" for "y".

3x + 2y = 6

2y = -3x + 6

y = -(3/2)x + 3

Now, since parallel lines have the same slope, you can set up your new equation, with the new points, using the same slope.

y - y1 = m(x - x1)

y - 10 = -3/2(x - 2

Again, solve for "y"

y - 10 = -3/2(x - 2

y - 10 = -3/2x + 3

y = -(3/2)x + 13 (<==ANSWER!!) :-)