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Math Help - Throwing a ball across a field problem.

  1. #1
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    Throwing a ball across a field problem.

    A ball is thrown across a field. Its path is given by the equation
    y = -0.005x^2 + x + 5
    where:
    y = height
    x = horizontal distance

    What is the max height reached by the ball?
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  2. #2
    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by needhelp75 View Post
    A ball is thrown across a field. Its path is given by the equation
    y = -0.005x^2 + x + 5
    where:
    y = height
    x = horizontal distance

    What is the max height reached by the ball?
    If you're familiar with calculus, find where \frac{\,dy}{\,dx}=0 and then plug that value into the original function to find the maximum height.

    Otherwise, you can use the fact that the vertex of a parabola occurs at the point \left(-\frac{b}{2a},f\left(-\frac{b}{2a}\right)\right)
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  3. #3
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    thanks for reply,
    vertex of a parabola looks more familiar,
    where do i go next?
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  4. #4
    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by needhelp75 View Post
    thanks for reply,
    vertex of a parabola looks more familiar,
    where do i go next?
    a=-0.005 and b=1

    In the point for the vertex, f\left(-\frac{b}{2a}\right) would yield the maximum height.

    Thus, f\left(-\frac{1}{2(-.005)}\right)=f\left(\frac{1}{.01}\right)=f\left(1  00\right)=\dots
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  5. #5
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    check please

    confirmed?

    horizontal distance = 100
    vertical distance = 55

    is this correct?
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  6. #6
    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by needhelp75 View Post
    confirmed?

    horizontal distance = 100
    vertical distance = 55

    is this correct?
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