Results 1 to 7 of 7

Math Help - Finding the distance between each pair of points

  1. #1
    Member
    Joined
    Sep 2006
    Posts
    99

    Finding the distance between each pair of points

    Find the distance between each pair of points

    (3,7) and (15,2)

    I've been taught y=mx + b, slope, y-intercept, x-intercept - straight lines only, degree 1.

    How do I solve the above? Since I know the values of x and y, is this finding the value of m and b?

    I don't know how to solve the above question. Please help.

    Thanks.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Grand Panjandrum
    Joined
    Nov 2005
    From
    someplace
    Posts
    14,972
    Thanks
    4
    Quote Originally Posted by shenton View Post
    Find the distance between each pair of points

    (3,7) and (15,2)

    I've been taught y=mx + b, slope, y-intercept, x-intercept - straight lines only, degree 1.

    How do I solve the above? Since I know the values of x and y, is this finding the value of m and b?

    I don't know how to solve the above question. Please help.

    Thanks.
    The points A=(3,7) and B=(15,2) together with C=(3,2) form a right triangle
    with the segment AB forming the hypotenuse (sketch this out on paper
    and you will see what is going on more clearly).

    The length of AC is 5, and of BC is 12, so by Pythagoras's theorem:

    AB^2 = 5^2 + 12^2 = 169,

    so AB=sqrt(169) = 13.

    Now that was the long way of doing it. If you look closly at what I did
    you will see that the distance between any two points A=(a_1, a_2)
    and B=(b_1, b_2) is:

    d(A,B) = sqrt[(a_1-b_1)^2 + (a_2-b_2)^2].

    RonL
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Member
    Joined
    Sep 2006
    Posts
    99
    Interesting, all the questions in the homework is about y=mx + b and this is one question that is different and I've not been taught the Pythagoras's theorem. But thanks for teaching me that.
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Forum Admin topsquark's Avatar
    Joined
    Jan 2006
    From
    Wellsville, NY
    Posts
    10,211
    Thanks
    419
    Awards
    1
    Quote Originally Posted by shenton View Post
    Interesting, all the questions in the homework is about y=mx + b and this is one question that is different and I've not been taught the Pythagoras's theorem. But thanks for teaching me that.
    I'm sorry? How could you be in Pre-Calc and not have been taught the Pythagorean Theorem? You've had basic (7th grade or so) geometry haven't you?

    -Dan
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Member
    Joined
    Sep 2006
    Posts
    99
    I never had high/middle school, just catching up what I've lost.
    Follow Math Help Forum on Facebook and Google+

  6. #6
    Forum Admin topsquark's Avatar
    Joined
    Jan 2006
    From
    Wellsville, NY
    Posts
    10,211
    Thanks
    419
    Awards
    1
    Quote Originally Posted by shenton View Post
    I never had high/middle school, just catching up what I've lost.
    No problem. I was just a little confused as to why this is in the "Pre-Calculus" room.

    -Dan
    Follow Math Help Forum on Facebook and Google+

  7. #7
    MHF Contributor Quick's Avatar
    Joined
    May 2006
    From
    New England
    Posts
    1,024
    Quote Originally Posted by shenton View Post
    Interesting, all the questions in the homework is about y=mx + b and this is one question that is different and I've not been taught the Pythagoras's theorem. But thanks for teaching me that.
    WHAT?!?!?!? I learned pythagoreum in 6th grade

    Anyway, just to let you know, the theorum says that given a right triangle with sides a, b, and c, where c is the hypotenuse (c is the largest side) then: a^2+b^2=c^2

    The distance formula makes it so that the distance between the two points is the hypotenuse, then the difference in height is a side, and the difference in width is a side. Thus the difference formula is: d=\sqrt{a^2+b^2} (you can see it is the pythagoreum theorum solved for c, which is d for distance in this case)
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Finding the distance between points
    Posted in the Algebra Forum
    Replies: 5
    Last Post: September 21st 2011, 01:49 PM
  2. Replies: 4
    Last Post: February 8th 2011, 11:37 AM
  3. Finding the distance between two points
    Posted in the Calculus Forum
    Replies: 3
    Last Post: November 7th 2009, 06:43 PM
  4. finding the distance between two points
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: June 19th 2009, 07:31 PM
  5. Finding distance between two points.
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: May 24th 2008, 01:43 PM

Search Tags


/mathhelpforum @mathhelpforum