he parabola x=y^2+ay+b crosses the parabola y=x^2 at (1,1) MAKING RIGHT ANGLES. WHAT ARE THE VALUES OF A AND B .

any help is greatly appreciated.

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- Dec 14th 2008, 04:13 PMshoroI need urgent urgent hel with this parabola question
he parabola x=y^2+ay+b crosses the parabola y=x^2 at (1,1) MAKING RIGHT ANGLES. WHAT ARE THE VALUES OF A AND B .

any help is greatly appreciated. - Dec 14th 2008, 04:48 PMmr fantastic
Since (1, 1) lies on $\displaystyle x=y^2+ay+b$ you know that

$\displaystyle a = -b$ .... (1)

To get another equation, I'd calculate the value of the gradient of the curves $\displaystyle x=y^2+ay+b$ and $\displaystyle y = x^2$ at (1, 1) and then set the product of the gradients equal to -1.

Now solve two equations simultaneously for a and b.