Hi, I'm not sure how to solve this one, I tired getting into quadratic form, but I ended up getting a cubic. :S 4^x + 12(2)^(-x) = 7
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Originally Posted by millerst Hi, I'm not sure how to solve this one, I tired getting into quadratic form, but I ended up getting a cubic. :S $\displaystyle 4^x+12(2)^{-x}=7$ $\displaystyle 2^{2x}+12(2)^{-x}=7$ Then multiply both sides by $\displaystyle 2^x$ $\displaystyle 2^{3x}-7(2^x)+12=0$ Let $\displaystyle 2^x$ be a $\displaystyle a^3-7a+12=0$ Then solve the equation ..
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