if you assume the origin at the center of the base with x passing through A and y passing through B and z passing through V. you can put A,B,C,V in position vector format
A--(2sqrt(2),0,0)
B--(0,2sqrt(2),0)
C--(-2sqrt(2),0,0)
V--(0,0,4)
ABCD is the base of a square pyramid of side 2 units, and V is the vertex. The pyramid is symmetrical, and of height 4 units. Calculate the acute angle between AV and BC, giving your answer in degrees correct to 1decimal place.
I do not necessarily need the full solution. I just need to change it into position vectors so that I can solve it using dot product (scalar product).
I was able to do it for some other shapes but I just can't think how to apply it on a pyramid.