Just wanna check if my answer is correct!
Find the first n second derivatives of the function: f(x)=x^3(5x^2+3)^2
f(x)=x^3(5x^2+3)^2
f^1= 3(x^2)(5(2x)+3)^2
=(3x^2)(10x + 3)^2
=(3x^2)(100x + 10 + 30x + 9)
=(3x^2)(130x + 39)
=130^3 + 117
No, it doesn't work like that. Revise the product rule and the chain rule in your textbook, or here:
http://www.mathhelpforum.com/math-he...-tutorial.html