I need to determine the domain of each function.
If you answer can you tell me how you did it?
$\displaystyle h(x) = \frac{1}{1-sin(x)}$
Thanks.
look at the denominator ...
are you familiar with the rule that says division by 0 is undefined?
if $\displaystyle sin{x} = 1$, what would be the value of the denominator?
so ... what does that tell you $\displaystyle \sin{x}$ cannot be equal to ?
domain is the set of all x-values that can be input into a function without breaking certain rules ... division by 0 is one of those rules that cannot be broken.
Yes I am familiar with that rule. I can see the answer being $\displaystyle x \neq 1$ in an equation that looks like this:
$\displaystyle h(x) = \frac{1}{1-x}$
but if I plug 1 in for x on my problem below, the denominator looks like this:
$\displaystyle h(x) = \frac{1}{1-sin(1)}$ = $\displaystyle \frac{1}{1-0.84147...}$
because sin(1) = 0.84147...
Am I missing something?