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find the point of intersection of the lines: 3x + 4y = -6 and 2x + 5y = -11
Quote: Originally Posted by heatherblack87 find the point of intersection of the lines: 3x + 4y = -6 and 2x + 5y = -11 3x + 4y = -6 2x + 5y = -11 use elimination multiply the first by -2 and the second by three (3x + 4y = -6)*-2 (2x + 5y = -11)*3 -6x-8y=12 6x+15y=-33 cancel the x's -8y=12 15y=-33 7y=-21 y=-21/7 y=-3 now sub to find x
Quote: Originally Posted by euclid2 3x + 4y = -6 2x + 5y = -11 use elimination multiply the first by -2 and the second by three (3x + 4y = -6)*-2 (2x + 5y = -11)*3 -6x-8y=12 6x+15y=-33 cancel the x's -8y=12 15y=-33 7y= - 21 y= - 21/7 y= - 3 now sub to find x Small corrections in red.
Quote: Originally Posted by mr fantastic Small corrections in red. I appreciate that, no wonder when i subed the y value the answer was so chaotic, lol