hi I have a problem,
sin^2x = 6(cosx +1)
how do i solve and get answer pi/3, /3 etc.
Start by substituting $\displaystyle \sin^2 x = 1 - \cos^2 x$.
Now re-arrange into a quadratic equation involving $\displaystyle \cos x$. Factorise and solve to get two equations for $\displaystyle \cos x$.
The only equation that leads to real solutions is $\displaystyle \cos x = 1$.