hi I have a problem,

sin^2x = 6(cosx +1)

how do i solve and get answer pi/3, /3 etc.

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- Dec 8th 2008, 05:41 PMcokeclassicTrig Equation help
hi I have a problem,

sin^2x = 6(cosx +1)

how do i solve and get answer pi/3, /3 etc. - Dec 8th 2008, 05:48 PM11rdc11
- Dec 8th 2008, 05:49 PMmr fantastic
Start by substituting $\displaystyle \sin^2 x = 1 - \cos^2 x$.

Now re-arrange into a quadratic equation involving $\displaystyle \cos x$. Factorise and solve to get two equations for $\displaystyle \cos x$.

The only equation that leads to real solutions is $\displaystyle \cos x = 1$. - Dec 8th 2008, 06:29 PMcokeclassic
Ahh I had it right! I was looking at the wrong answer! (Lipssealed)

Thank you very much